I. If 150mL of a 17% (W/V) concentrate of benzalkonium chloride are diluted to 5 gallons,...

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I. If 150mL of a 17% (W/V) concentrate of benzalkonium chloride are diluted to 5 gallons, what will be the strength of the di

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Answer 1

Answer #1

Q.

ANS. - total Available solution of benzalkonium is 150 ml.(Q1)

Concentration of solution is 17%(C1) should be diluted in 5 gallon (Q2)

Note 1 gallon is 4000 ml, so 5 gallon = 5×4000

=20000 ml or 20 liter

Formula is Q1×C1=Q2×C2

150×17=20000×X

X=150×17÷20000

X= 2550÷20000

X= 0.127% is the right answer.

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Answer 2

Answer #2

1gal = 3785mL 3785mL x 5 =18925mL 150 x 17 = 18925 x X X= 0.1347 RS= 1:742

answered by: anonymous

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Answer 3

Answer #3

1gal = 3785mL 3785mL x 5 =18925mL 150 x 17 = 18925 x X X= 0.1347 RS= 1:742 w/v

answered by: anonymous

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Answer 4

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