CC of A = 500000 + 35000/ 0.12 + 350000 * (A/F, 12%,10) / 0.12
= 500000 + 35000/ 0.12 + 350000 * 0.056984 / 0.12
= 957870.48
CC of B = 700000 + 25000/ 0.12 + 450000 * (A/F, 12%,15) / 0.12
= 700000 + 25000/ 0.12 + 450000 * 0.026824 / 0.12
= 1008924.23
As CC of A is less, it should be selected
Economic Analysis ewnan restion (2) Jse capitalized cost to determine which type of oad surface is...
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1. An economic analysis is used to determine the profitability of a machine. Assume the minimum attractive rate of return (interest rate) is 3%. What is the present worth of this investment alternative? Initial cost = $11,000 Estimated life = 7 years Salvage value = 3,800 Annual maintenance cost = 475 Annual income = 1,800 Income gradient = 120 a.PW = $3,500 b.PW = $2,450 c.PW = $2,500 d.PW = $2,350
please solve both
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