Question

For the circuit be low, compute: - the input impedance Za; - the voltage Vc Zg A Vc Zoe Zoe Zc E ZA D Z.o2 YD I- Data: E-10 V (peak value) YD (0.00275-j0.00 1) S 2.8x10 m/s (for all the lines) AB 4 cm Zc-(25-j25) Q Zo2= 200 f= 7 GHz BD-1.04 cm Zg-100Q Zol 100 Q BC 3 cm

Answer 1

A R 2-001 2 do Yo 2u +2o tan (CAL) -Part D n | 20 + J2 tan(pl) 2 002 is tuken B Io Promm Pait inpot impednke it's and sepatats raratt 2in is dulevm'ined 20 tan ( Bl ) 2 o 2 in= 2« tun (p1) 2o 200n 20 269 9930 YD O. O 0.000 2S - 2 7 BL JJ3JJ

3%10 u.28T B 2n isanceD 27 2 T x.O4 S26 Tadion. a56 t930 00) tan i-5267) (256+330 an ( 1-5267) J 200 200 S 4538.23) 2S6 3230 2003(256 +3930)x Q2 5a 256 I5 - 2090I- 5808 64 J RS6u763j .49-42.9

leryth ranmission l'ine 2in 20 2o0 20+2 han 27) X U 28 anB) 3.140 200 8.14D 2S J2S+ in)ec (25-05 C3.1uo) 200 t 2S.12 3 J40 ) 1- J 8 62A 26.12 - j IIIU0-3- 140j (An)ec a19.5 + 52-9 j Anal dicircuit wo0ld be 2 9 A A in Bc in6o)

21 (219.5 +52.93) || -49-42.9) 1 (219.5 +52.9 3) C949- U2.9) ) (219.5152-9) 2 TI X uoj) .27 1.29 40j + 100 CO43sa) in )n 2io A 2in A - 35.35 - 36. 59 Í (2in)A Voltage acyyos 2in A E X - 35.3 S-36.59j 6u. 6S 36.59j Vc 66-30 3V V 2 -1,315-