Question

using simple and basic C++

I.(a) A 6 X6 array, arr, is filled to capacity with integers. Write code to find and print: (i) the sum of the negative integers in the array. (ii) the main diagonal values. Only ONE for loop can be used for printing the main diagonal values. Example of main diagonal for a 3 X3 array: 5 2 7 2 3 6 Major or Main Diagonal (iii) interchange the values of the first and second columns. [10 marks] Write a function that accepts a string (b) according to the following cipher/coding scheme: input and enciphers (encodes) the string as chox ch sh ntr rine a. Convert the entire string to upper case. b. Reverse the capitalized string c. Shift each letter upward two places alphabetically, (wrapping the alphabet around), so that 'A' becomes 'C', 'X' becomes 'Z', 'Z' becomes 'B, and so on. Example: The text message "abxzyc" becomes "EABZDC" Assume that the input string contains letters only. [10 marks] Assume that the string is NULL terminated. [TURN THE PAGE]

Answer 1

Note: Could you plz go through this code and let me know if u need any changes in this.Thank You
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a)

#include <iostream>
#include <cstdlib>
#include <ctime>
using namespace std;

int main(){
   srand(time(NULL));
   const int SIZE=6;
   int negNosSum=0;
int arr[SIZE][SIZE];


for(int i=0;i<SIZE;i++)
{
    for(int j=0;j<SIZE;j++)
    {
        arr[i][j]=rand()%(21)-10;
   }
}

cout<<"____ Displaying the array ___"<<endl;
for(int i=0;i<SIZE;i++)
{
    for(int j=0;j<SIZE;j++)
    {
    cout<<arr[i][j]<<"\t";  
            if(arr[i][j]<0)
            {
                negNosSum+=arr[i][j];
           }
}
cout<<endl;
}
  
cout<<"Sum of Negative Values :"<<negNosSum<<endl;
cout<<"Displaying the diagonal Elements :";
for(int i=0;i<SIZE;i++)
{
    for(int j=0;j<SIZE;j++)
    {
        if(i==j)
        {
            cout<<arr[i][j]<<" ";
       }
    }
}
cout<<endl;
int temp;
   for(int i=0;i<SIZE;i++)
   {

           temp=arr[i][0];
           arr[i][0]=arr[i][1];
           arr[i][1]=temp;
      
   }
   cout<<"____ Displaying the array after Interchanging first and second columns___"<<endl;
for(int i=0;i<SIZE;i++)
{
    for(int j=0;j<SIZE;j++)
    {
    cout<<arr[i][j]<<"\t";  
            if(arr[i][j]<0)
            {
                negNosSum+=arr[i][j];
           }
}
cout<<endl;
}
  
return 0;
  
}

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Output:

CAProgram Files (x86)\Dev-Cpp\MinGW64\bin\ArraySumOfNegativeNosDiagonalElements.exe Displaying the array 9 -9 -10 2 -10 2 Sum of Negative Ualues-89 3 4 3 -9 9 10 -9 8 6 6 8 -9 -3 -8 -10 10 2 Displaying the diagonal Elements :-3 6 -10 -3 10 2 Displaying the ay after Interchanging first and second columns arr 4 3 -9 9 10 -9 3 1 -9 1 1 -9 -10 2 -10 6 8 -3 -9 3 -8 10 10 2 Process exited after 0.1041 seconds with return value 0 Press any key to continue T

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b)

#include <iostream>
using namespace std;

string getInput();
void convertToUpper(string &str);
void reverseString(string &str);
void upwardTwoPlaces(string &str);
int main(){


string res=getInput();
   cout<<"Result :"<<res<<endl;
  
return 0;
  
}
string getInput()
{
   string str;
   cout<<"Enter String :";
   cin>>str;
   convertToUpper(str);
   reverseString(str);
   upwardTwoPlaces(str);
   return str;
}
void convertToUpper(string &str)
{
   string s="";
   char ch;
   for(int i=0;i<str.length();i++)
   {
       ch=str.at(i);
       if(ch>='a' && ch<='z')
       {
       s+=ch-32;  
       }
       else
       {
       s+=ch;  
       }
   }
   str=s;
}
void reverseString(string &str)
{
   string rev="";
   for(int i=str.length()-1;i>=0;i--)
   {
       rev+=str.at(i);
   }
   str=rev;
  
}
void upwardTwoPlaces(string &str)
{
   string s="";
   for(int i=0;i<str.length();i++)
   {
       if(str.at(i)=='Y')
       {
           s+='A';
       }
       else if(str.at(i)=='Z')
       {
           s+='B';
       }
       else
       {
           s+=str.at(i)+2;
       }
   }
   str=s;
}
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Output:

CAProgram Files (x86)\Dev-Cpp\MinGW64\bin\ConvertLowerToUpperReverseString.exe Enter String :abxzyc Result EABZDC Process exited after 9.587 seconds with return value Press any key to continue

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