Question

Need it in C language

C Arrays Chapter 6 268 6.20 (Game of Craps) Write a program that runs 1000 games of craps (without human interven- tion) and answers each of the following questions: a) How many games are won on the first roll, second roll, ..., twentieth roll and after the twentieth roll? b) How many games are lost on the first roll, second roll, ..., twentieth roll and after the twentieth roll? c) What are the chances of winning at craps? [Note: You should discover that craps is onc of the fairest casino games. What do you suppose this means?] d) What's the average length of a game of craps? e) Do the chances of winning improve with the length of the game?

Answer 1

#include <stdio.h>
#include <stdlib.h>

enum game{Continue, Won, Lost};
// dice rollturn
int roll()
{
int sum=rand() % 7 + 1+rand() % 7 + 1;
return sum;
}
// display
void display(int won[], int lost[], int countwin, int countlose)
{

int count=countwin+countlose; // total loss and wons
int gamelength=0;
for(int i=0; i<21; i++) // run loop for 21 times
{
// display after 21 wins and loss
if(i==21)
{
printf("\n******Roll after 20 *****");
printf("\nGames won :: %d",won[20]);
printf("\tGames Lost :: %d",lost[20] );
}
// display before 21 wins and loss
else if(i<21)
{
printf("\n******Roll Turn Number %d *****",i+1);
printf("\nGames won :: %d" ,won[i]);
printf("\tGames Lost :: %d",lost[i] );
}
// calculate length of game
gamelength = gamelength + (won[i]*i+1 + lost[i]*i+1);
}
printf("\nChances of winning game :: %d" ,(countwin*100/count));
printf("\nThe average game length is %0.4f rolls.\n", ((float)gamelength/(float)count));

}
  
void gameofcraps(int won[], int lost[], int countwin, int countlose)
{
int total=0;
int points=0;
enum game g;
int rollturn;
// run 1000 times
for(int i=0; i<1000; i++)
{
rollturn=0;
total=roll();
// check win or loss
switch(total)
{
case 7:
case 11:g=Won;
break;
case 2:
case 3:
case 12:g=Lost;
break;
default:g=Continue;
points=total;
break;
  
}
// check if gams is to be Continued or not
while(g==Continue)
{
total=roll();
rollturn++;
if(total==points)
g=Won;
else if(total==7)
g=Lost;
}
// for turm >21
if(rollturn>=21)
rollturn=20;
if(g==Won)
{
won[rollturn]++;
countwin++;
}
else
{
lost[rollturn]++;

countlose++;
}

}
// call display
display(won, lost, countwin, countlose);

}
int main()
{
int won[21]={0};
int lost[21]={0};

int countwin=0;
int countlose=0;
gameofcraps(won, lost, countwin, countlose);

return 0;
}

Output

*Roll Turn Number 10 * ** Games Lost:: Games Won 6 8 k***Roll Turn Number 11 * **** Games Lost:: Games won 7 9 **Roll Turn Number 12 *k** Games won 6 Games Lost :: 6 :: k***Roll Turn Number 13 **** Games won 4 Games Lost :: 4 :: k***Roll Turn Number 14 * **** Games won 8 10 Games Lost :: k***Roll Turn Number 15 * **** Games Lost:: Games won 2 4 *** Roll Turn Number 16* Games won 1 Games Lost :: 3 :: ******Roll Turn Number 17 **** Games won 1 Games Lost :: 3 :: ******Roll Turn Number 18 * * Games won 1 Games Lost :: 2 :: ******Roll Turn Number 19 * * Games won Games Lost:: 1 :: 0 ******Roll Turn Number 20 ** * Games won Games Lost:: 1 2 :: ****Roll Turn Number 21 ** Games Lost:: 6 Games won : 4 Chances of winning game 50 : The average game length is 3.1730 rolls.