Question

An oscillating current in an electric circuit is described by I=9e^-t sin(2pi*t). Determine all values of t such that I=3.5

From problem 6.18 in the book: Solve for the root using the bisection method, initial values x, = 0.35 and x, 0.45 and a stopping criterion &=0.5%. Start by rearranging the equation to set it up for root finding if I=3.5. Report your answers to 3 decimal places. Note: use radians for the sine component. iter xl eal (%) xu 0.35 0.45 4 1 N/A 35 .4 375 6.667 2 3 4 6 What is the value of the root? % What is the relative approximate error?

Answer 1

+ 0.06 X N f(t)=9 exp(-t) sin(2u)-3.5 0.04- o.02 (0.1013,0) 0.38 0.32 o 0.3 0.46 0.34 0.36 0.42 0.44 -0:02 -0.04- desmos

Reomranging equation: - - 3.5 ge sim (2nt) Co.35,0.45 i.6303 flo,35) = f Co.us) tm- O.4 C.o4C (+ flo.4) Co.y,o.S -o.8281 (-) t(tm) Co..0.425 o.4125 -o,3869 ftm) - i o.u.0.125 tm e.4 o63 (-) tm o.1709 G.403 Co.u,o.40637 -0.0664 -) o.yo IC Co.4,0.4031 0.8 79 x 02 fltm (-1) - o,6087q O.00S vi) Co.4,0.401 O.4008 tm o.o18 6 (t) O.00S tm .4o12 0.492 x 12 t1tm) O OO 49 2

O.OoS let's Stop here Yoot is O.4o12
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