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Suppose that the average U.S. household uses 14600 kWh (kilowatt-hours) of energy in a year. If the average rate of energy co

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Answer #1

Solution)

Part a)

We know,

Average power, P=E/t =(14600*1000)/(365*24)

P=1666.66 Watts

We also know,

time, t=Mgh/P =(2130*11.3*9.8)/1666.66

T=141.52 sec

=======

Part b)

Time, t = mgh/Pavg

   = (3.9*10^5 kg )(9.8 m/s^2)(9920 m)/(1666.66W)

  = 2.27*10^7 s

==========

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