Question

If T is a kinetic energy, p is the length of a momentum vector and v is the length of a velocity vector of a particle with mass m show that:

$\frac{pv}{T}=\frac{T+2mc^{2}}{T+mc^{2}}$

Answer 1

The total energy & kinetic energy T is related ar, E = T + mc² and we know E= 8 mc² (2) with 8 – - (3) and and so pe 8mv ² - p²c² + m²c4 - (4) puse pike to using (3) to le n moet) wing (8) - 'ca ((t+ mez)? - m?cm) using cos timei (1? + 27mca) - 7° + 2 Tmc? using (e) - T(T+2 mc²) using (1) T + mc2 : quod . T + 2mc? T + mc² T # 203.2 (sas)