Question

Question 3.

Write a program that contains the following functions a) A function that takes in as input the amount a person has to pay to buy a house, and the monthly payments made. Your function should display how much has been payed and how much is left to pay every month until the mortgage has been payed (Ignore interest and the like) b) A function that takes in as input the color of a car, and returns the number of cars of that color present in a file that contains the color of cars parked in a lot. Create the file, and put in color of cars (the number of entries doesn't matter, but make sure there is repetition) E.g Blue Red Blue Green Black Red ............. and so on c) A function that returns the color of car that is most present in the parking lot d) A function that takes in two colors as input and returns the total number of cars with both colors. For example, if there are 7 blue cars and 5 silver cars, your function should return 12.

Answer 1

Dear student, according to the question, the solution is as follows:

Program:

#include <iostream>
#include <fstream>
#include <unistd.h>
#include<string.h>

using namespace std;
int NumberofColorCars(char*);
int NumberofColorCars2(char*,char*);
void houseMonthlyPayments(int,int);

int main()
{
houseMonthlyPayments(120000,3);
cout<<"No. of cars of color Blue are : "<<NumberofColorCars("Blue")<<endl;
cout<<"No. of cars of color Blue and color Red are : "<<NumberofColorCars2("Blue","Red");
return 0;
}

int NumberofColorCars(char *color)
{
std::ifstream myfile("Carcolors.txt");
if ((!myfile))
{
std::cout << "Failed to open file\n";
exit(1);
}
char ch[100];
int count =0;

while(myfile>>ch)
{
if((strcmp(ch,color)) == 0)
{
count++;
}
}
return count;
}

int NumberofColorCars2(char *color1,char *color2)
{
std::ifstream myfile("Carcolors.txt");
if ((!myfile))
{
std::cout << "Failed to open file\n";
exit(1);
}
char ch[100];
int count = 0;

while(myfile>>ch)
{
if( (strcmp(ch,color1) == 0) || (strcmp(ch,color2)) == 0 )
{
count++;
}
}
return count;
}

void houseMonthlyPayments( int bought, int n)
{
// Assuming 12 months installment.
int installment = bought / 12;
int paid = (n * installment);
int left = (bought - paid) / (12 - n);
cout << "Bought @ : " <<bought<<endl;
cout << "Paid till now : " <<paid<<endl;
cout << "Total no. of months to be paid :" <<(12- n)<<endl;
cout << "Left to pay every month :" <<left<<endl;
cout<<endl;
}

Output:

Bought : 120000 Paid till now: 30000 no. of months to be paid :S9 ft to pay every month :10000 Le No. of cars of color Blue are 5 No. of cars of colorBlue and color Red are 12

first 4 lines represent part a) function

5th line represent part b) function

6th line represents part d) function

Bought : 240000 Paid till now : 100000 Total no. of months to be paid :7 Left to pay every month :20000 No. of cars of color Blue are 5 No. of cars of color Blue and color Red are : 12

Sorry for the inconvenience, I couldn't able to complete part C function.

Thank you, All the best.