Question

d271 0 IX MONT TWO BEADS, EACH OF CNPE Q, ME PLACED IN A BOWL TAT DOB Nut CONDUCT. THE BOWL His RABIUS R. THE BEADS REPEZ ENCN There UNTIL They mee R PISTANCE APART, FIND Q IN TERMS OF R AND FUNDAMENTAL CONSTANTS. MINT ; THE BEADS AND PowL ARE SAME AS AN INCLIVE WITH AN ANGLE You cat FIOU PE Outi

Answer 1

Solutions d e o let the mass of a bead P8 m. and it make$ an angle with horizontal Lyx (90- F I zát

EFxzo - NBPne = F -0 E Fy=0 = N COBE = mg - © from ② x② tang- Fing -

Since the bead P8 on a Circular curved bowl. normal on bead par bey through centre. , we bee using . Geometry angle go-o= 60° * 10 = 30° . put e=30° in ein ② - Tanso = 5 mg 92 = ng tango 4Mto

og tan 30°) R2 477 60 + Q=\(4m 6o) R2 mg tar 30 → Q = R11411€.) mq ton 30°
please give positive feedback response. Thanks