By mirror formula
1/u + 1/v = 1/f
Here u=2f
Then 1/v = 1/f - 1/2f
=1/2f
v=2f
Magnification =-v/u
=-2f/2f
=-1
Then so image size is -2cm
When an object is at the center of curvature C of a concave mirror. The imagen is the same height but inverted.
So:
y' = -2.0 cm
Option d is correct !!
There will be an induced electric Held hal is clocl (e) CHAPTER # 25 11). An...
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Chapter -25 The Reflection of Light: Mirrors 3 - A coin is placed in front of a concave mirror that has a radius of curvature R-0.50 m The image of the coin is inverted and is five times larger than the size of the object. Determine the distance between the coin and the mirror (de). a) 0.10 m b) 0.15 m c) 0,20 m d) 0.30 m e) 0.45 m 4 - A concave mirror of radius R-54 em...
need help. please answer #8-11
8. As an object moves away from a plane mirror on a wall and you observe the object and the image from the position of the mirror, the image of the object A. gets smaller B. may or may not get smaller, depending on where the observer is positioned. C. Is always a real image, no matter how far you are from the mirror. D. Changes from being a virtual to a real image as...
1) A 21.0 cm tall cup is placed 77.3 cm away from the center of a concave mirror with a focal length of 47.0 cm . What is the height of the cup's mirror image? image height cm? 2) You have a concave spherical mirror with a 12.7 cm radius of curvature. You place an object on the mirror's axis, 19.7 cm in front of the mirror. How far is the object's image from the mirror? -If it can be...
Chapter 25, Problem 16 Your answer is partially correct. Try again. Concept Simulation 25.2 illustrates the concepts pertinent to this problem. A 2.80-cm-high object is situated 14.5 cm in front of a concave mirror that has a radius of curvature of 14.8 cm. Calculate (a) the location and (b) the height of the image (a) Numberi74 (b) Number-2.40 Units cm Units cm
11. A ray of light strikes a thick sheet of glass (n-1.5) at an angle of 25° with the normal. Find the angle of the ray reflected off the glass surface with respect to the normal. a. 56 b.46 c.39 d. 25 12. A fiber optic cable (n- 1.s0o) is submerged in water (- 1.33). What is the critical angle for light to stay inside the cable? 2. 83.1 b.62.5 С. 41.8 d. 27.6 13. An object placed 12 cm...
8. A 2.0-cm high object is situated 14.5 cm in front of a concave mirror that has a radius of curvature of 8.0 cm. What is the height of the image?
Q.4 (a) Write down the formula that relates the object and image distance to the focal length for a concave, spherical mirror and identify all terms used. [4 marks] (b) Define the terms paraxial ray and spherical aberration of a concave mirror. How can the shape of the mirror be adjusted to eliminate this aberration? [3 marks] (c) A certain concave spherical mirror has a radius of curvature of 10.0 cm. A box with height of 3.0 cm is located...
An object 2.35 cm tall is placed 2.60 cm in front of a spherical concave mirror with a radius of curvature equal to 10.4 cm. Calculate the image distance ?I. Calculate the image height ℎI.
the A constant electric current to bote the recircular loop of wire as shown vention that the arrow indicating the direction of current is drawn in the loround of the dico). A smaller powe r ed through the center of the larger loop Based on this diagram answer Question 6 below. draw ascow on this loce Bind Question 6: As the small wire loop approaches the larger loop, which direction will the induced current flow in the small wireloop? Please...
Ап object 2.0 mm tall is placed 6.0 cm from the front of a CONCAVE MIRROR. The radius of curvature is 9.0 cm 2. (3 points) What is the focal length of the mirror a) b) Describe the image, including: The image's distance from the mirror in centimeters: Magnification How do you know? Real or virtual? How do you know? Upright or inverted? How do you know? Larger, smaller, or same size as object?
Ап object 2.0 mm tall is...