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4. Let x be a random variable that represents the length of time it takes a student to complete a chemistry lab project. From

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4)
P(X >= 4.5) = P(z <= (4.5 - 3.6)/0.5)
= P(z >= 1.8)
= 1 - 0.9641
= 0.0359

5)
Here, μ = 3.6, σ = 0.5/sqrt(6) = 0.2041 and x = 3.
We need to compute P(X >= 3). The corresponding z-value is calculated using Central Limit Theorem

z = (x - μ)/σ
z = (3 - 3.6)/0.2041 = -2.94

Therefore,
P(X >= 3) = P(z <= (3 - 3.6)/0.2041)
= P(z >= -2.94)
= 1 - 0.0016
= 0.9984

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