Solid Ca(IO3)2 is added to 0.0100 M KIO3. Titration shows that the concentration of iodate in...
Solid Ca(IO3)2 is added to 0.0100 M KIO3. Titration shows that the concentration of iodate in the solution is now 0.0150 M IO3-. a) What portion of the iodate concentration was derived from the dissolving of calcium iodate? b) What is the concentration of calcium created by the dissolving solid?
Homework Answers
a) Portion of Iodate concentration derived from Ca(IO3)2 = Concentration of IO3- - Concentration of KIO3
=> 0.0150 - 0.0100
=> 0.0050M
b) So, on dissolving Ca(IO3)2, the concentration of IO3- is increased by 0.050M
On dissolving, Ca(IO3)2 will split as below
Ca(IO3)2 ================= Ca(2+) + 2IO3-
Concentration of calcium created = 1/2 * concentration increase of IO3- = 1/2 * 0.050 = 0.025 M
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