Question

Compare the molecules OF, OF-, and OF+, discussing molecular orbitals, bond order, bond lengths, bond energies, and paramagnetism.

Answer 1

The molecular orbital configuration the given compounds are: OF rightarrow sigma_2s^2 sigma_2s^*2 sigma_2p_x^2 pi_2p_y^2 pi_2p_y^2 pi_2p_z^*2 pi_2p_y^*1, OH^circledotoperator rightarrow sigma_2s^2 sigma_2s^*2 sigma_2p_x^2 pi_2p_y^2 pi_2p_z^2 pi_2p_z^*2 pi_2p_y^*2, OF^+ rightarrow sigma_2s^2 sigma_2s^*2 sigma_2p_x^2 pi_2p_y^2 pi_2p_z^2 pi_2p_z^*2 bond order: 1/2 (no. of bonding electron - no: of antibonding electron) OF rightarrow 1/2 (8 - 5) = 1.5: OF^circledotoperator rightarrow 1/2 (8 - 6) = 1 OF^+ rightarrow 1/2 (8 - 4) = 2 therefore bond order is OF^+ > OF > OF^circledotoperator bond length with the increase of bond order, bond length decreases. So, the order is OF^circledotoperator > OF > OF^+ bond energy: - greater the bond order, greater the bond energy OF^+ > OF > OF^circledotoperator Paramagnetic: - As, we can see from the configuration number of unpaired electron is 1, 0, 0 for OF, OF^circledotoperator and OF^+ respectively. So, the paramagnetic ion is: OF