Question

Considering the amount of FeCl2 and FeCl3 and an NH3 solutions used, which reagent was the limiting reagent in this reaction? Show calculations to support your answer.

2 FeCl3 + FeCl2 + 8 NH3 + 4 H2O → Fe2O4 + 8 NHACI The surfactant used in this synthesis is tetramethylammonium hydroxide. 4.0mL of 10m Fells used CH₂ 1. Ome of 2.om Fell zused NICH3 | 50mL of 1.om Nitsused [" CH₃ J Tetramethylammonium hydroxide

Answer 1

hy) Ron & 2 Fellat Fellyt & Nhz +420 Fe₂O₃ + 8 Nhyld a) moles of fell - malarity & Volume = 4MX 4 X10 L = 4X10² mol b) moles of NH₃ = 1M X 50X10} = 5x10 mol. c) moles of Fell = 2MX1X10" L = 28103 mol. Sdution & the best of a) find limiting Reagent & a) moles here Coff of fella = moles - 4x10ml Cofficient 2 22x10-3 (lowest) b) molis heu copt. of NH3 = 5X102= 6-25*10*3 c) males per Coff of Fell2 = 24 10 3 = 24103 (lowest . mole pere coff. of Pe de and fell i Lowest, so, both acts as limiting Rea limiting Reagents = Feldz and feet eo - Result