Two mutually exclusive water purification systems are being considered for implementation overseas. Refer to the data below:
|
System 1 |
System 2 |
|
|
Capital investment Annual revenues Annual expenses MV at end of useful life Useful life |
$100,000 $50,000 $15,000 $20,000 13 years |
$150,000 $75,000 $20,000 0 26 years |
If MARR = 30 % per year, determine the present worth (PW) of the most profitable water purification system to use. Use the repeatability assumption. (Enter your answer as a number without the dollar sign.)
PW of system 1 = -100000 - 100000(P/F, 30%, 13) + 20000(P/F, 30%, 13) + 20000(P/F, 30%, 26) + (50000 -
15000)(P/A, 30%, 26)
= -100000 - 80000*0.033017 + 20000*0.001090 + 35000*3.3297
= $13,920.
PW of system 2 = -150,000 + (75000 - 20000)(P/A, 30%, 26) + 0(P/F, 30%, 26)
= -150000 + PV(30%,26,-55000,0)
= $33,133.48
The present worth (PW) of the most profitable water purification system to use is $33,133.48 (system 2)
Two mutually exclusive water purification systems are being considered for implementation overseas. Refer to the data...
preferred? Assume repel 6-34. Potable water is in short supply in many countries To address this need, two mutually exclusive water purification systems are being considered for implementation in China. Doing nothing is not an option. Refer to the data below and state your key assumptions in working this problem (6.5) System 7 System 2 Capital investment $100,000 $150,000 Annual revenues 50,000 Annual expenses MV at end of useful life 20,000 Useful life 70,000 22,000 40,000 5 years 16.5% 10...
Two mutually exclusive design alternatives are being considered for purchase. Doing nothing is also an option. The estimated cash flows for each alternative are given below. The MARR is 10% per year. Using the PW method, which alternative, if either, should be recommended? Capital Investment Annual Revenues Annual Expenses MV at end of useful life Useful Life IRR Alternative 1 $15,000 $8,000 $2,900 $2,000 4 years 17.2% Alternative 2 $23,000 $12,000 S3,000 $800 12 years 38.4%
Potable water is in short supply in many countries. To address
this need, two mutually exclusive water purification systems are
being considered for implementation in China. Doing nothing is not
an option. Assume the repeatability of cash flows for alternative
1.
a. Use the PW method to determine which system should be
selected when MARR = 7% per year.
b. Which system should be selected when MARR = 15% per
year?
a. The PW of system 1 is $_______. (Round...
* Question Completion Status: Mutually Exclusive Alternative Four mutually exclusive alternatives are being evaluated, and their costs and revenues are itemized in Table a. If the MARR is 15% per year and the analysis period is 12 years, use the PW method to determine which alternatives are economically acceptable and which one should be selected? Capital Investment Annual Revenues less expenses Market Value (end of useful life) Useful life (years) $150,000 15,200 10,000 $125,000 31,900 $200,000 35,900 15,000 $100,000 41,500...
The following data have been estimated for two mutually exclusive investment alternatives, A and B, associated with a small engineering project for which revenues as well as expenses are involved. They have useful lives of 3 and 5 years, respectively. If MARR = 10% per year, show which alternative is more desirable by using equivalent-worth methods. Use the repeatability assumption. Project A B Investment $5,000 $6,000 Cash flow/yr $1,450 $1,600 Usual Life 3 5 Salvage value $500 $500
Consider the following EOY cash flows for two mutually
exclusive alternatives (one must be chosen). The MARR is 5% per
year.
I need the PW of the Lead Acid and Lithium Ion.
Problem 6-28 (algorithmic) EQuestion Help Consider the following EOY cash flows for two mutually exclusive alternatives (one must be chosen) The MARR is 5% per year ead Acid $7,000 thium lon Capital investment Annual expenses Useful life Market value at end of useful life $13,000 $2.500 $2,750 12...
Consider the mutually exclusive alternatives given in the table below. MARR is 8 % per year. Assuming repeatability, what is the equivalent annual worth of the most profitable alternative? (Do not enter the dollar sign $ with your answer.) _____________________________________________________________ X Y Z _____________________________________________________________ Capital investment $80,000 $40,000 $64,000 Annual savings $24,000 $12,800 $19,200 Useful life (years) 8 12 16
ANSWER THE FOLLOWING QUESTIONS:-
Three mutually exclusive design alternatives are being considered. The estimated cash flows for each alternative are given. The interest rate is 20% per year. At the conclusion of the useful life, the investment will be sold A C Investment cost $28,000 $55,000 $13,000 $28,000 $8,000 $40,000 Annual expenses Annual revenues $15,000 $23,000 $6,000 10 years $22,000 $32,000 13 $10,000 Salvage value Useful life 10 years 10 years A decision-maker can select one of these alternatives or...
USE
ANNUAL WORTH Analysis
Two mutually exclusive design alternatives are being considered. The estimated cash flows for each alternative are given in the following table with MARR = 10% per year. Suggest your recommendation by using multiple attribute annual worth AW analysis. Design A Design B Investment cost (RM) 28,000 55,000 One-off expenses 10,000 13,000 In year 4 (RM) Annual revenues (RM) 22,000 28,000 Market value (RM) 6,000 8,000 Useful life 10 years 6 years
2) Two mutually exclusive design alternatives are being considered, with each one having a useful life of 10 years. The estimated sales and cost data for each alternative are shown. Annual revenues are based on the number of units sold and the selling price. Annual expenses are based on the fixed and variable costs. If the MARR is 20% per year, determine which alternative is preferable based on the PW Method. 12 Investment cost Units to be sold each year...