Question

CCSF Introductory Statistics Econ. 5 Chapter 10 Practice Assignment Name: Harry's Hamburgers claims that the residents of Harryville eat at the hamburger chain an average of exacty 18 6mes per year. You took a sample of 48 residents of Harryvile and found that the sample mean was 17. The sample standard deviation was 4.5. You want to test to see if Harry's claim can be dasputed with a significance level o o.05 1. For each number in with that number a. 18 b.48 c 17 e.0.05 State the null and alternative hypotheses 2. 3. How many tails is this test? 4. Specify a 5. Give the symbol for the test statistic and compute the value. 6. How many degrees of fre edom are there? 7. Use the t table to find a range for the p-value. 8. What is your conclusion using the p-value approach in statsticalterms? 9. What is your condlusion in business terms? 10. Now do the problem using the confidence intervall approach and state your conclusion in statistical terms MacBook Air

Answer 1

solution

1.

a.)18=μ

b.)48=n

c.)17=x̅

d.)4.5=s

e.) 0.05=α

2.)Null Hypothesis, H₀: μ=18

Alternative Hypothesis, H₁ : μ ≠ 18

3.) Two Tailed Test

4.)Significance Level(α)=0.05

5.)Test Statistic(t):

$t=\frac{Xbar-\mu }{s/\sqrt{n}}$

$t=\frac{17-18}{4.5/\sqrt{48}}$

$t=-1.54$

6.) degree of freedom (df)=n-1=48-1=47

7.)p-value=2*[P(t<-1.54, df=47])=.1303 (use student t table)

8.) P-value is greater than the significance level(α=0.05),  we fail to reject the null hypothesis H₀

9.)we fail to reject the null hypothesis H_0, There is no enough evidence to support the claim.

I have solve 9 parts of the problem here for the rest please repost