Question

PLEASE ANSWER WITH MATLAB

Determine the perimeter of an ellipse with a 3 and b-9 For the triangle shown, a-200m, b-250m, and c 300m. Define a,b,c,as variables and then a. Calculate the angle e (in degree) by using The Law of cosine 2. (Law of Cosine: c2-a2+b-2abcos( e)) b. Calculate radius r of the circle inscribed in the triangle using the formula: r-(a+b+c)/2.tan(0/2) Calculate the radius r using the formula c. s(s-a)(s-b)(s-c) where s (a+b+c)/2

Answer 1

The formula is part b is not clear in the pic.

Considering the formula is r= (a+b+c)/(2*tan(y/2)) following is the solution

a = 200;
b= 250;
c=300;
y=acosd((-(c^2)+(a^2)+(b^2))/(2*a*b));
disp("The angle Phi by law of cosine is"+y);
r=(a+b+c)/(2*tan(y/2))
disp("The radius as calculated from first equation is"+ r)
s=(a+b+c)/2;
l=s*(s-a)*(s-b)*(s-c);
z=sqrt(l);
r2=z/s;
disp("The radius as calculated from second equation is"+ r2)

Considering the formula is r=((a+b+c)/2)*tan(y2/2) following is the solution

a = 200;
b= 250;
c=300;
y=acosd((-(c^2)+(a^2)+(b^2))/(2*a*b));
disp("The angle Phi by law of cosine is"+y);
r=((a+b+c)/2)*tan(y/2);
disp("The radius as calculated from first equation is"+ r)
s=(a+b+c)/2;
l=s*(s-a)*(s-b)*(s-c);
z=sqrt(l);
r2=z/s;
disp("The radius as calculated from second equation is"+ r2)