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35.35 2120 What is the molecular formula of a compound that contains 10.0 g carbon, 1.68 g hydrogen, and 13.4 g oxygen? The m

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Answer #1

1). To find the molecular formula, the following steps are to be followed:

Step 1: Change the given masses to moles

Given:

Carbon = 10.0 g

Hydrogen = 1.68 g

Oxygen = 13.4 g

For Carbon:\frac{10.0g}{12.0 g mol^{-1}} = 0.833 moles

For Hydrogen:\frac{1.68 g}{1.0 g mol^{-1}} = 1.68 moles

For Oxygen:\frac{13.4 g}{16.0 g mol^{-1}} = 0.83 moles

Step II: Find a ratio between the moles to determine the empirical formula

The ratio of Carbon and Oxygen is 1:1 as

\frac{0.833}{0.833} = 1

Next, the ratio of Hydrogen to both Cabon and Oxygen is 2:1

\frac{1.68}{0.833} = 2

So the ratio is 1 C to 1 O to 2 H

Therefore the empirical formula comes out to be CH2O.

Step III: Finding the Molecular Formula

From the empirical formula calculated above, i.e., CH2O the molar mass comes out to be 30.0 g mol-1 as

12 g (C) + 2*1 g (H) 16g (O) = 30.0 g mol-1

But the given molar mass of the compound is 60 g mol-1. Therefore, we need to multiply the emperical formula by 2 to get this molar mass of 60 g mol-1.

Therefore, the molecular forula of the compund is C2H4O2. Hence, Option (C) is the correct option.

2). A solution is diluted by adding more amount of solvent in it while keeping the amount of solute constatnt. Therefore option (A) more is the correct option

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