Question

The acid dissociation constant K of boric acid (H,BO2) is 5.8 x 100. Calculate the pH of a 4.3 M solution of boric acid. Round your answer to 1 decimal plac pH = 0 I Don't Know Submit

Answer 1

Ausur - I ce tuble 13 Bog + + er) H2B93 4.3 M Inited Change Fauilibrium an 4.3-1 ka = SH] [F_BO] (43003] 5.9 x 10-19 = 7? 4.3- Since Ka is very low so zaze 4.3 5.8 X10-10 22 4.3 a = 4-994 x 10-5 M pHP -log 147] (H+) = m = 4.994 x 10-5 ply a vlog (4.994 210-5) TpH = 4.30