Question

Please complete the lab following the guidelines using JAVA

Activity 1 Write a program called AnalyzeNumbers. This program will have array that holds 10 random integers from 1 to 5. Output the 10 random numbers to the screen using an enhanced for loop. This program will also have a method called frequency that takes an integer array as the parameter and it will return an array that holds the frequency of numbers. Index 0 will hold the frequency of 1, index 1 will hold the frequency of 2, and so on. Use this method in your program to create an array that holds the frequency of the random numbers in your array. Use an enhanced for loop to output the frequency of each number. Then display the number that appears the most in your array-you will need to account for numbers appearing the same amount for the mode.

Answer 1

Math.random() with ranges​

(int)((Math.random()*(max-min+1))+min)

Example

Range 5-10 max is 10 min is 5

Max-min+1=10-5+1=6

(int)((Math.random()*6)+5)

In the above question range is 1-5

Max-min+1=5-1+1=5

(int)((Math.random()*5)+1)

Program

public class AnalyzeNumber{
static int freqarray[] = new int[5];

public static void main(String[] args) {
int i=0;
  
int array[]=new int[10];// to store 10 integers
for( i=0;i<10;i++)
{ array[i]= (int)((Math.random()*5)+1); //store 1-5 random numbers

}
System.out.println("Random number are");
  

for(i=0;i<10;i++)
{ System.out.println(array[i]); //store 1-5 random numbers
}

// AnalyzeNumber ob = new AnalyzeNumber();
frequency(array);
System.out.println("Frequency of number are");
  
for( i=0;i<5;i++)
{
System.out.println("frequency of "+ (i+1)+" is "+freqarray​[i]);
}
}
  
static int[] frequency (int arr[])
{
  
  
  
for( int i=0;i<5;i++)
{
freqarray[i]=0;// for counting initial value to be zero
}
  
for( int i=0;i<10;i++)
{
for(int j=0;j<5;j++)
{ if(arr[i]==(j+1))// checking integer value from1-5
freqarray[j]++;}
  
}
return freqarray;
}
}

Output for the given program

Random number are
4
4
5
5
4
3
4
4
3
1
Frequency of number are
frequency of 1 is 1
frequency of 2 is 0
frequency of 3 is 2
frequency of 4 is 5
frequency of 5 is 2

Explanation

run program and see the comments

if(arr[i]==(j+1)) // if array value is checked from 1to 5

// j is the position which so position 0 checks for 1 (j+1) //frequency
freqarray[j]++; // to count frequency of j+1 and store and //increment at position j

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