13.) Option 'A' is correct.
We will use the concept of compound interest.
A= P*(1+r/100)n
Where, A= Amount after 'n' years .( Also called future value)
P= Principal value( Present value)
r= rate of interest.
n= number of years.
Here,
A=$600,000,r=12%,n= 4 years
Substituting in the above formula,
$600,000= P*(1+12/100)4
P=($600,000)/(1+0.12)4 = ($600,000)/(1.12)4 = $600,000/1.5735 = $381,310.84
Thus, now the company should spend $381,310.
Therefore, Option 'A' is correct.
14.) Option 'B' is correct. Closest to 14 years .
We can use either ,A/P factor or P/A factor.
Using A/P factor,
$60,000(A/P,10%,n) = $8000
(A/P,10%,n) =$8000/$60,000= 0.133
(A/P,10%,n) = 0.133
From Compound interest table(you can download the table from Google) , we can get the value of (A/P,10%,n)
On looking in the table for 10% , corresponding value of 'n' for (A/P,10%,n)=0.133 is in between 14 and 15.
So, closest value of 'n' is 14 years.
Therefore, Option 'B' is correct.
Question 13 A company needs an amount of $600,000 four years from now. How much could...
Timed Test This test has a time limit of 1 hour. This test will save and submit automatically when the omdeles. Warnings appear when half the time, 5 minutes, 1 minute, and 30 seconds remain. Multiple Attempts Not allowed. This test can only be taken once. Force Completion This test can be saved and resumed at any point until time has expired. The timer will continue to run if you leave the test. Remaining Time: 34 minutes, 00 seconds. Question...
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