ANSWER:
Ans:
1)sample proportion
=58/300
=0.1933
Test statistic:
z=(0.1933-0.1667)
(0.1667*(1-0.1667)/300)
z=1.239
critical z value=+/-1.96
Fail to reject the null hypothesis.
There is not sufficient evidnece to conclude that the die is not fairly balanced.
2)
lower cut off=0.1667-1.96*
(0.1667*(1-0.1667)/300)
=0.1245
upper cut off=0.1667-1.96*
(0.1667*(1-0.1667)/300)
=0.2089
when true p=0.25
z(0.1245)=(0.1245-0.25)
(0.25*(1-0.25)/300)
=-5.02
z(0.2089)=(0.2089-0.25)
(0.25*(1-0.25)/300)
=-1.645
P(type II error)=P(-5.02<z<-1.646)
=P(z<-1.646)-P(z<-5.02)
=0.0498-0.0000
=0.0498
I need answer part 2 1. A die is rolled 300 times; it lands five 58...
1. A die is rolled 300 times; it lands five 58 times. Suppose that the true chance of landing five is 0.25. Draw the picture to state the region of β, which is the probability of making the Type II error.