Question

A 1.80-kg object is held 1.15 m above a relaxed, massless vertical spring with a force constant of 315 N/m. The object is dropped onto the spring. (a) How far does the object compress the spring? 0.396x Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error. m (b) Repeat part (a), but this time assume a constant air-resistance force of 0.650 N acts on the object during its motion. 0.3507x Your response differs from the correct answer by more than 10%. Double check your calculations. m (c) How far does the object compress the spring if the same experiment is performed on the Moon, where g = 1.63 m/s2 and air resistance is neglected? Cm

Answer 1

mass m=108kg, height h=115 m, k= 315 N/m pe of object = ingh = 1-8X9-8X1-15 = 20-286 J Let the spring compressed by 'y' meter, from law of conservation of energy ' P. E of spring = 1ky² = 20-286 => y = /28 20:286 y = 2*20.286 = 0.359 m 315 (b) constant air desistive force =065n Work clove in opposite direction of motion for h=115m) = 0-6581-15 30.7485 Total energy = 20.286-0-748 = 19.538 5 Spring compression y=[2x19-538 . .=0.353m 315 (e) pe o object = mgh = 1-8 x1-63x15 = 3-374. I Spring compression y = (2x 3-374 20.146 m 315