Homework Answers
We have to find molar concentration (molarity) of acetic acid in 5% vinegar solution.
Given :
Density of vinegar = 1.08 g/mL
Molar mass of acetic acid = 60.05g
Volume of solution = 100mL
Volume of vinegar (acetic acid) = 5mL
Solution :
Mass of acetic acid = density * volume
= 5mL * 1.08 g/mL = 5.4g
Moles of acetic acid = 5.4/ 60.05 = 0.08992
Molarity = no. of moles of solute(mol)/ volume of solution(L)
= 0.08992/0.1
=0.899M
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I
think the answer is 3.94% but I don’t know if that is right, and I
don’t have any work to support it
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