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MYBCCC/Home 111535537 Spring 2019_PHY 101 704:2 Problem 5.03 Part A A horizontal force of 340 N is exerted on a 2 5 kg ball a
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Answer #1

here,

mass ,m = 2.5 kg

radius , r = 0.9 m

let the speed of ball be v

the horizontal force , F = 340 N

m * v^2 /r = 340

2.5 * v^2 / 0.9 = 340

solving for v

v = 11.06 m/s

the speed of ball is 11.06 m/s

55)

mass , m = 7 kg

separation , d = 35 cm = 0.35 m

the magnitude of gravitational force , F = G * m * m /d^2

F = 6.67 * 10^-11 * 7 * 7 /0.35^2

F = 2.668 * 10^-8 N

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