Question

ULIC Wu uye. 4) W + 2x + 3Z (W]=.25M [X]=.10M (Z]=.30M k = 9.0 x 10^ Find Qc, Find kp, 5) 0.5m BaBr2, 0.5m NaF, 0.5m CO2, 0.5m CH3COOH Which has the a) lowest freezing point, b) greatest vapor pressure, c) arrange by increasing boiling point. 6) D + E +> F (fast/eq) D + G (slow)

#5
0.5m BaBr2, 0.5m NaF, 0.5m CO2, 0.5m CH3COOH
Which has lowest freezing point, greatest vapor pressure, and arrange by increasing boiling point.

I got boiling/freezing points
CO2 < CH3COOH < NAF < BaBr2

So greatest would be CO2
But I am confused by CH3COOH and NaF, both have van hoff of 2 so how do we know which boiling point is higher?

Answer 1

© r = [z] = (0:30) - Tous [w] [x] (0-20) (0-100% Pc = 10.8 3-3 My = ke (2734n = (9.0x164) (0.00114298) xp = 9.0x164 (0-042 X 298 xp = 9.0x104 6 @ lowest freezing point : 0.5m Babra 6 © greatest vafour pressure? o.sm co Smeresting boilony bont : Co, < CH3COOH < Naf < Baby | here: Nafi value = 2 o but et, cooh is the weak electrolyte and its degree of Sanitation is very small so I value is not equal to 2 . So Naf has higher B.P. Scanned with CamScanner