int a[5]; a[4] = 3; for (int i=3; i >= 0; i--) { a[i] = 2*a[i+1]...

Question

Question

int a[5];

a[4] = 3;

for (int i=3; i >= 0; i--) {

a[i] = 2*a[i+1] - i;

cout << a[i]; }

engineering Computer-Science

Answer 1

Answer #1

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Answer 2

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