Question

Truss ICA 9 4/40 Determine the force in member BF. 30° 15° 9 kips 3 kips 54 st to st Problem 4/40

Answer 1

solution! - - g kipst No.– 150 1 3 kips! st tano = EN FN 25ft where; BN 2 BM + MG + NG 2 stan 30o & Stanis & Stanis = 5.566 ft in temo - $566 5KG o tai leima) - 41.982 50 x 420

Now, consider Joint a {fx=0; FAB cos30° + fag costs=0 1 Pro AB ZA = 0; FAn sin 30 = 9+ FAG sin15 T30° FAG solving ea no. 0 & 9 g Kips FAR Cosso & FAG Cosis = 0 FAR sin 30 - FAG siste = - x san15 wsis FAR COS 30 Sints & FAG coses saints=0 Ai sino coseso - FAG sinds cosso = g cosir (+) FAB Sim (38 +15) = gcosis FAB = 12.29 kips in from ey no. 0; 12.29 casso & FAQ Cosis = 0 FAG = - 11.02 kips

FBC Cos30' cosy & for sin la cos42 a 12.29 cosso cosur Fac sur 30 sing2 - for cosu sinh 2 = 3 si 42 + 12.29 sin 30 en 12 be sure (t) For cos (42-30) = 14 Thec e 14. 34 lips from equo. . ; 14.34 cos 30" & fap sur 42 - 12.20 cos30° On (KAT in For = -2.653 kips (OR) For a 2.653 lips you
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