Question

r is placed into a pot of boiling water. After 60 seconds in the pot, the thermometer reads 100° C and is removed. Which method would cool the thermometer the fastest? (1 pt) a. i. Placing the ermometer in a room-temperature water bath Exposing the thermometer to room-temperature air ii. (ifi) Exposing the thernometer to room-temperature air and an electric fan b. Name the heat transfer mechanism of the method you selected above. (I pt) c. Using the same cooling method, would it take longer for the thermometer to from 100° C to 75 C or from 50° C to 25° C? Why? (2 pts) to cooo

Answer 1

Hi,

Hope you are doing well.

PART (a):

(i) Placing the thermometer in a room temperature water bath will cool its faster since the water has more specific heat capacity.

PART (b):

This method of heat transfer is known as Conduction.

PART (c):

It will take more time to cool from $50^{o}C$ to $25^{o}C$.

Since $25^{o}C$ is very close to room temperature, their temperature difference will be very small. So according to Newton's law of cooling we can say that, It will take more time to cool from $50^{o}C$ to $25^{o}C$ than from $100^{o}C$ to $75^{o}C$.

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