The average score of all pro golfers for a particular course has a mean of 71...

Question

Question

The average score of all pro golfers for a particular course has a mean of 71 and a standard deviation of 3.0. Suppose 36 pro

math Statistics-And-Probability

Answer 1

Answer #1

Answer:

Given,

To determine the probability that the average score of 36 pro golfers is lessthan 70

Here mean = 71

standard deviation = 3

n = 36

sqrt(n) = 6

Now,

P(xbar < 70) = P(Z < (70 - mean) /(s/sqrt(n)))

substitute the values

= P(Z < 70 - 71/( 3/6))

= P(Z < - 2)

Required probability = 0.0228

Answer 2

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