Question

A pinball bounced around its machine before resting between two bumpers. Before the ball came to rest, its displacement was recorded as a series of vectors. All the angles are measured counterclockwise from the horizontal x-axis.

A pinball bounced around its machine before resting between two bumpers. Before the ball came to rest, its displacement was recorded as a series of vectors. All the angles are measured counterclockwise from the horizontal -axis. V: 83.0 cm at 90.0° Vz: 59.0 cm at 143 Vs: 69.0 cm at 229 Find the magnitude and direction of the ball's total displacement. magnitude: direction:

Answer 1

Solchon clost wise Au A vector R makeny angle a coith a og in represented by contrcloskw R REK [uro + sneg] Now in our case for u,, & Resulfandant of these vectors 3- the tu = (cose, î+ sine, }] o [caso it sing ) t uz [copozit & n, i] = [U, wxo, i + v coxs tu coxz 21 - (V, sino + Y sind + zsind, I putting given Volwes. = [ 830 cm X Cosso + 59.0cm x cox cho +690 anx cox 229) ? - [ 8300cm X singo't 5gram X sin 143 + 69.00mx sin 229] , = – 92.38 cm ê + 6643 m a

I nequetude 13) = √(- 92.38 m ) 2 + (66143002 = 113.78 cm Ang mee dreckm: Angle with x axis in conter clockwise drechon 66.43cm - 92.38cm U = 194.28 foren