Question

Please show how to work this problem

Consider two cars traveling on the highway, one behind the other. They are both moving at the same initial velocity, vi-29.1 m/s, with the first car a distance d in front of the second car. ("d" is the distance from the front bumper of the second car to the back bumper of the first car.) At some time the driver of the first car hits the brakes and comes to a stop with an acceleration a1-1.67 m/s The driver of the second car doesn't immediately notice the first car slowing down, and keeps driving with the velocity v, for a time At-2.44 s. The second driver then slams on the brakes and comes to a stop with an acceleration a2--1.37 m/s2 What is the smallest distance d (the "following distance") such that the second car just touches the first car. (You can use the approximation that the final position of the front bumper of the second car is equal to the final position of the back bumper of the first car.) Give your answer in meters to at least three digits to avoid being counted wrong due to rounding (Hint: The two cars do not stop at the same time.)

Answer 1

一つ253.536 m, Car2 入1-37 28 2x1.3구 380 0587 m m a d -SB-94 つ390, 05 8구-253.536 -' つ 126'523 m.