Question

Show the calculation of the number of moles of formula units in 0.30 grams of LiCl and the number of ions of each element in the 0.30 grams

Answer 1

We know that for any compound the onship between the mole and the mass gelationship betwee or that is - na M m Where na no. of mole of the compound ma mass of ŕ that compound M = Molar mass of that compound we know that Molah mass of Liel is M = 42.394 g/mol By the problema mass of Liel is a m = 0.30gm - 0.30 gm them, n = 42.394 g/mol n = 7.07 8 10-3 moi 5o, in 0.30gm of Liel 7.07x10-3 mole of Liel is Present Licl - littch- Foo'm this we can see that Lich consiste of one lition and one ar- ion. As we know that a 1 mole of a substance contains 6.023x10 230. atoms or molecules 30, 7.07x10-3 mole of Lich contains a = 7.0 74 10 3 X 6.0 23x10 23 no. of Lict = 4.25 X 102 no. of liel molecules molecules

A3 Licl consists of one Lition and one cits ion. 30, In 4.25x10 21 no. of Lich molecules also have - 4.25 x 1021 no. of Lition and .4.25 X 10 21 no. of cr-ion