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assuming sum of mother and father's age is 80
hence sd = 80
mean = 1288
Z = (X - mean)/sd = (X - 1288)/ 80
P(X > 1250)
P(X > x) = 0.375
P(Z > z) = 0.375
z = 0.385
x = mean + z* sd
= 1288 + 0.385 * 80
sd(Xbar) = sd(X) /sqrt(n)
P(Xbar < 1225)
= P(Z < (1225 - 1288)/(80/sqrt(200))
= P(Z < -11.1369)
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2. Chilicheese Games scores arç normally distributed with a mean of 1288 and a standard deviation...
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