rate = 1/2 [NOBr] /
t =
[Br2] /
t
[NOBr] /
t = 2.24 x
10-2 M/s
substitute these value in above expression
1/2 (2.24 x 10-2) = [Br2] /
t
[Br2] /
t =
1.12 x 10-2 M/s
For the decomposition of nitrosyl bromide at 10 °C 2 NOBr(g)2NO) +Br2(g) the average rate of...
References Nitrogen monoxide, NO, reacts with bromine, Br2, to give nitrosyl bromide, NOBr. 2NO(g) + Bra(9) - 2N0Br(9) A sample of 3.74 x 10-2 mol NO with 3.11 x 10-2 mol Br2 gives an equilibrium mixture containing 2.31 x 10-2 mol NOBr. What is the composition of the equilibrium mixture? mol NO mol Br2 mol NOB Submit Answer Try Another Version 7 item attempts remaining
2NOBr(g) ⇆ 2NO(g) + Br2(g) If nitrosyl bromide, NOBr, is 25.48 percent dissociated at 25°C and the total pressure is 0.325 atm, calculate KP and Kc for the dissociation at this temperature.
2NO(g) + Br2(g) = 2NOBr(g) Experiment [NO-] (M) [Br2] (M) Initial Rate (M s-1) 1 0.10 0.20 24 2 0.25 0.20 150 3 0.10 0.50 60 4 0.35 0.50 735 1.) Determine the rate law equation for the reaction. 2.) What is the overall order of the reaction? 3.) What are the value and the units of the rate constant, k? 4.) Write the expression to show how is the rate of disappearance of bromine, Br2, related to the rate...
The decomposition of nitrosyl bromide (NOBr) has an equilibrium constant, Kc, equal to 3.07 x 10-4 at 24oC according to the equation: 2NOBr(g)D 2NO(g) + Br2(g) . Which of the following system compositions is at equilibrium at 24oC? ( ) [NOBr] = 0.0610M, [NO] = 0.0151M, [Br2] = 0.0108M ( ) [NOBr] = 0.115M, [NO] = 0.0169M, [Br2] = 0.0142M ( ) [NOBr] = 0.181M, [NO] = 0.0123M, [Br2] = 0.0201M ( ) [NOBr] = 0.0450M, [NO] = 0.0105M, [Br2]...
Nitrosyl bromide decomposes according to the following equation. 2NOBr (g) ↔ 2NO (g) + Br2 (g) A sample of NOBr (0.64 mol) was placed in a 1.00-L flask containing no NO or Br2. At equilibrium the flask contained 0.21mol of NOBr. How many moles of NO and Br2, respectively, are in the flask at equilibrium? a) 0.21, 0.21 b) 0.43, 0.43 c) 0.22, 0.42 d) 0.43, 0.22 e) 0.21, 0.11 Please show all work/steps
In a study of the decomposition of nitrosyl bromide at 10 °C NOBr—+NO+ Br2 the concentration of NOBr was followed as a function of time. It was found that a graph of 1/[NOBr] versus time in seconds gave a straight line with a slope of 1.27 m?s and a y-intercept of 3.98 M? Based on this plot, the reaction is order in NOBr and the rate constant for the reaction is M?? In a study of the decomposition of hydrogen...
The decomposition of nitrosyl bromide at 10 °C NOBrNO + ½ Br2 is second order in NOBr with a rate constant of 0.800 M-1 s-1. If the initial concentration of NOBr is 0.390 M, the concentration of NOBr will be_______ M after 8.54 seconds have passed.
1. In a study of the decomposition of nitrosyl bromide
at 10 °C
NOBr ---> NO + ½
Br2
the following data were obtained:
[NOBr], M
6.71×10-2
3.36×10-2
1.68×10-2
8.40×10-3
seconds
0
20.9
62.8
147
Hint: It is not necessary to graph these
data.
(1)
The observed half life for this reaction when the starting
concentration is 6.71×10-2 M is _______
s and when the starting concentration is
3.36×10-2 M is
s.
(2)
The average (1/[NOBr])
/ t from t...
The gas phase reaction of nitric oxide, NO, with bromine, Br2,
to produce nitrosyl bromide, NOBr,
occurs according to the net reaction: A possible reaction
mechanism is:
?1
Step 1: 2 NO ⇌ N2O2
?−1
Step 2: N2O2 + Br2
2NO+Br2 → 2NOBr
2 NOBr
Neither step is faster than the other. What is the order of the
overall reaction, and what is the overall rate constant (expressed
in terms of the individual rate constants for the elementary
steps)?
9....
For the gas phase decomposition of nitrosyl chloride at 400 K 2 NOCI +2 NO + Cl2 the following data have been obtained: NOCI), M time, h 1.61x102 10 7.49x10-3 33.7 4.88x103 67.4 3.62x10 101 The average rate of disappearance of NOCl over the time period from t = 33.7 h to t = 67.4 h is Mh! Submit Answer Retry Entire Group 9 more group attempts remaining For the decomposition of dinitrogen pentoxide in carbon tetrachloride solution at 30°C...