Question

2.) In a recent year, Delaware had the highest per capita annual income with an average of $51,800 and Annual per capita income is normally distributed in Delaware. $1850. (a) If a resident is randomly selected, what is the probability that their income is less than $50,000? Let X be the salary of a randomly selected Delaware resident. Write an inequality that represents the scenario described in (a). DIX< 50.000)=0.3553 Properly shade the bell, set-up, and solve the problem. m=51,800 6= 4450 50.000 - 51,800 P(x<50, 4850 =p/Z<-0.371)

Answer 1

Page Given : ef=51800 o=4850 xo Annual income per capita PCX < 50000) - P(x-4 < 50000-4 ) NCON 0-3557 P/ Z < 50000-51800 4850 P(Z <-0.3711) = I-P(aco.711) - from Zrtable = 1 - 0.6443 0.3557 -0.370 At na 10 PX> 52000 52000-4 on oln = Prz > 52000-518001 4850 /NTO 4483 = = 1533-7047 Pizzo 1304) - P(Z <0.1300) from z-table 1-0.5517 2013 = TPCM 752000) 0.4483