Question

Problem 4 (15pts): (a) (5pts) Consider the following MIPS memory with data shown in hex, which are located in memory from address 0 through 15, Show the result of the MIPS instruction "Iw Ss0, 4(Sa0)" for machines in little-endian byte orders, where Sa0 8 Address Contents Address Contents 4¢ 8 c5 6d 1 9 2 7e 8f 66 10 70 11 8a Oa 12 13 14 15 1b a3 b4 2c 6 3d 7 (b) (10pts)Assume we have the following time, performance and architecture parameters in the specified units. Ec execution time in eycles/program Es- execution time in seconds/program Pr-performance rate in instructions/seconds CCT-clock cycle time in second/cycle CR-clock rate in cycle/second IC-instructions in instructions/program CPI average cycles per instruction in eycle/instruction Complete the following formulas with the appropriate parameter х СРIx ССТ ICx CPI, CR-1/ Es=

Answer 1

Answer a

$lw \;\;\$s0, 4(\$a0)$

=> $$s0 = M[\$a0 + 4]$

=> $$s0 = M[8 + 4]$

=> $$s0 = M[12] = 8a$

Answer b

Clock Rate (CR) = 1/CCT

• Clock cycle time and clock rate are reciprocal to each other

E_c = IC * CPI

• Product of total instructions count per program and clock per instruction will give total clock cycles per program

E_s = IC * CPI * CCT

• Product of Clock cycles per program and clock cycle time will give execution time in seconds.