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21 (1 point) If Y X and every Xi is i.i.d with a chi-squared distribution with 14 degrees of freedom, find the MGF of Y М()-

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Balotica x= {xi, xinxhiu tha y= 3Xinu važiuses) y = nx (294) We know the mq fg Gamma (2,3) MxCD= (1-$+7 If d= h and B=2 thouMyle) = (1+2+ j-147 =) Yo Chamma ( 2=147, B=2.) option (A) is correct. A

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