Question

PA 3-3 (Static) Consider a process consisting of three... 

Consider a process consisting of three resources. Assume there exists unlimited demand for the product. 

• Resource 1 has a processing time of 6 minutes per unit. 

• Resource 2 has a processing time of 3 minutes per unit. 

• Resource 3 has a processing time of 5 minutes per unit. 

The three resources are staffed by different workers individually. The flow diagram is shown above. 

Round "Capacity of resource" to 3 decimal places. 

a. What is the capacity of resource 2?  

b. What is the bottleneck in the process? 

c. What is the utilization of resource 2? 

d How long does it take the process to produce 200 units starting with an empty system, assuming this is a worker-paced process?

Answer 1

ANSWER :


Resource 1 takes 6 minutes to process 1 unit.

Resource 2 takes 3 minutes to process 1 unit.

Resource 3 takes 5 minutes to process 1 unit.


a.


Capacity of resource 2  (per hour) 

= Time of 1 hour / time needed for one unit

= 60 min. / (3 min. / unit)

= 20 units per hour (ANSWER).


b. 


Bottleneck is that resource which takes maximum time per 
unit.

In this case it is resource 1 which takes maximum time of 
6 minutes per unit.

So, bottleneck is resource 1. (ANSWER).


c.


As per bottleneck, capacity of the system is restricted to = 60/6 = 10 units per hour.

Capacity of resource 2 is 20 units per hour, but it has to do 10 units only in one hour.

Hence, 

Utilisation of resource 2 = 10/20 = 0.5 = 50% (ANSWER).


d.


System capacity is 10 units per hour.

So, 

Time needed to produce 200 units 

= 200/10 = 20 hours (ANSWER).

Answer 2

a.

Capacity of resource 2 = 1/3 = 0.333 units per minute

b.

Resource 1 is bottleneck as it is slowest of all the machines

c.

As demand is unlimited, flow rate is equal to process capacity so, utilization of resource 2 = flow rate/capacity of resource 2 = process capacity/capacity of resource 2 = ((1/6)/(1/3))*100 = 50%

[process capacity = 1/6 units per minute]

d.

First unit will take = 6+3+5 minutes = 14 minutes as process cycle time = 6 minutes per unit. rest of the 199 units will take 199*6 = 1194 minutes

So total time = 1194+14 = 1208 minutes