Question

Problem 1 Every line in the file grades.txt has the following structure: name homework scores quiz scores test scores The scores are separated by commas. The overall grade is calculated based on 20% for homework scores, 30% for quiz scores, and 50% for test scores. Write a function called transform that reads the lines of the grades.txt file and returns a dictionary with keys of type string and values of type dictionary. { 'Scott': { 'Homework : (100.0, 100.0, 90.0), 'Quiz' : [92.0, 88.0, 77.0), Test' : 198.0, 92.0, 100.0) ), def transform(): Problem 2 Write a function called student average that takes a string name and returns the grade of the corresponding student. ): def student average (name): # YOUR CODE HERE raise Not ImplementedError() ): assert student average ('Tyler') =74.5 assert student_average (Ming') - 67.05 assert student average( 'Daniel') 72.35 assert student_average('Marcia') - 72.1

Answer 1

Solution to Problem 1 is given below along with documentation:

------------------------------------------------------------------------CODE-------------------------------------------------

def transform():
   D={}
   file=open('grades.txt')
   for i in file:
       L=i.split("|")
       name=L[0]
       '''
           By using map() function we can map the values
           present in the List to a function
           let the line be
           'Scott|100.0 100.0 90.0|92.0 88.0 77.0|98.0 92.0 100.0'
           so now
           L=['Scott','100.0 100.0 90.0','92.0 88.0 77.0','98.0 92.0 100.0']
           now using map() we can convert the string literals into floating point literals
       '''
       homework_scores=list(map(float,L[1].split()))
       quiz_scores=list(map(float,L[2].split()))
       test_scores=list(map(float,L[3].split()))
       temp_dict={ 'Homework':homework_scores,\
                   'Quiz':quiz_scores,\
                   'Test':test_scores }
       D[name]=temp_dict
   return D

#the following print() is to test the function
print(transform())

--------------------------------------------------------END-------------------------------------------------------------------

Code in sublime text:

/grades.py - Sublime Text (UNREGISTERED) Edit Selection Find View File Tools Project Preferences Help Goto grades.py cons.py def transform ( ) : D {} file=open ('grades.txt for i in file: L=i.split ("|") name L[0 மா 3 6 7 By using map ( ) function we can map the values present in the List to a function let the line be 'Scott|100.0 100.0 90.0192.0 88.0 77.0| 98 .0 92.0 100.0' so now L=[ 'Scott','100 .0 100.0 90 .0' , '92.0 88.0 77.0','98.0 92.0 100.0 ] now using map ( ) we can conve rt the string literals into floating point literals 8 10 11 12 13 14 15 homework sco res-list (map ( float , L [ 1 ] . split ( ) ) ) quiz_scores=list (map ( fl oat , L [2] . split ( ))). test_scores=list (map ( float , L [3] . split ( )) temp dict={ 'Homework': homewo rk sco res,\ 'Quiz' : quiz_scores,\ 'Test':test_scores } 16 17 18 19 20 D[name]=temp_dict 22 23 return D 24 #the following print() is to test the function print(transform ( ) ) 25 26 Line 26, Column 19 Tab Size: 4 Python

OUTPUT:

gm@localhost: Terminal Help Search File Edit View gm@localhost:~$ cat grades.txt Scott|100.0 100.0 90.0|92.0 88.0 77.0|98.0 92.0 100.0 Alice|30.0 20.0 10.0|100.0 80.0 96.0|67.0 95.0 87.0 gm@localhost : ~$ python grades.py {'Scott': {'Homewo rk' : [100.0, 100.0, 90.0], 'Quiz': [92.0, 88.0, 77.0], 'Test': [98.0, 92.0, 100.0] }, 'Alice': {'Homework': [30.0, 20.0, 10.0], 'Quiz': [100.0, 80.0, 96.0], 'Test': [67.0, 95.0, 87.0] gm@localhost:-$

Solution for the Problem 2:

--------------------------------------------------------------------------CODE-----------------------------------------------

def student_average(name):
   details=transform()
   student_grades=details[name]
   L=student_grades['Homework']
   hs=sum(L)/len(L)*0.2
   L=student_grades['Quiz']
   qs=sum(L)/len(L)*0.3
   L=student_grades['Test']
   ts=sum(L)/len(L)*0.5
   avg=hs+qs+ts
   return round(avg,2)

#the below print() is for testing
print(student_average('Scott'))

---------------------------------------------------------------END----------------------------------------------------------

Code in sublime text:

/grades.py - Sublime Text (UNREGISTERED) Find View File Edit Selection Tools Project Preferences Help Goto grades.py cons.py 24 25 def student average(name): details=trans fo rm ( ) student_grades=details [ name] L=student_grades ['Homework' hs=sum(L)/len ( L) *0 . 2 L=student_grades['Quiz') qs sum (L)/len (L) *0 . 3 L=student_grades ['Test'] ts=sum (L)/len (L) *0 . 5 avg=hs+qs+ts return round ( avg , 2 ) 26 27 28 29 30 31 32 33 34 35 36 37 #the below print ( ) is for testing print(student_ave rage ( ' Scott ' ) ) 38 39 Line 39, Column 32 Tab Size: 4 Python

OUTPUT:

gm@localhost: Terminal Help File Edit Search View gm@localhost:~$ python grades.py 93.37 gm@localhost:~$

Have a nice Day...............:D