Question

Could you please show me how I can drw those circuits.

please using (NI Multisim 14)

Optocoupler Objectives Use an ohmmeter to determine the condition of the optoisolator. Observe the operation of an optocoupler. Determine the maximum frequency response of the optocoupler. Required Materials (1) Dual DC power supply (1) Function generator (1) Oscilloscope (2) Multimeters (1) Optocoupler (ECG3040) (1) 3.9ΚΩ resistor (1) 220 resistor Introduction An optoisolator is a hybrid integrated circuit that contains an LED on one side and a photodetec- tor on the other. The entire IC is hermetically sealed and light tight. It is called an optoisolator because it is used to electrically isolate a low-voltage circuit from a high-voltage circuit or one low-voltage circuit from another. A low-voltage control circuit is used to energize the LED Light from the LED is then optically coupled to the detector, which is used to control a secondary circuit. For this reason, optoisolators are also called optocouplers or optical coupling devices. Optocouplers isolate sensitive circuits, such as computer chips, from the hazards associated with con- trolling high-voltage and high-power circuits. They offer the advantages of separating high-voltage circuits from low-voltage circuits, blocking power circuit voltage spikes from returning to the control circuit, and preventing ground loop problems in data and control systems. They are capable of safely isolating 5-volt computer circuits from hundreds of volts in the output circuit. Optoisolators are also relatively inexpensive, take up little space, and greatly simplify control circuitry. In this lab exercise the operation of the optoisolator using a transistor as the detector will be observed. Procedure When light from the LED is off, the phototransistor will not be on, causing the resistance between the emitter and collector to be extremely high. Step 1 Using Figure 6-1 as a reference, place an ohmmeter between the emitter and collector with the LED off. The negative lead should be on the emitter, the positive lead on the collector, and the ohmmeter

Answer 1

The answer to the design problem is given below:

Theory: The probe and resistor should be connected as shown below to get 0 V when push-button is pressed and to get 15 V when push-button is not pressed.

Explanation: When push-button is pressed, Optocoupler is activated and the resistance between  Emitter and Collector is very less, so 15 V gets applied to 3.9 Kohm resistance. The probe reads 15 V.

When push-button is released, High resistance appears across Emitter & Collector. No current flows. So, the probe reads 0 V.

S1 4 O- V2 R1 15.0V 1 220 3 V1 U1 5.00V PR1 2 7 R2 3.90k2 0