38. The same calorimeter used in #37 was used to find the heat flow associated with the dissolution of 24g of NaCl in 176g of water. The observed ∆T (for both the calorimeter and the solution) was -1.6K. The calorimeter heat capacity is 60 J/K. The specific heat of the resulting NaCl solution is 3.64 J/Kg. What is the heat flow for this process?
38) q = Ccal * ΔT + m * cp * ΔT
We calculate the mass involved:
m = 24 g NaCl + 176 g H2O = 200 g
cp = 3.64 J / g * K
ΔT = -1.6 K
Ccal = 60 J / K
We substitute and calculate:
q = 60 * (- 1.6) + 200 * 3.64 * (-1.6) = -1260.8 J.
38. The same calorimeter used in #37 was used to find the heat flow associated...
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