Question

8Ω 3ον (+

Use the following figure to answer questions 1 through 5:

1. Find V1

a) 2V

b) 4V

c) 6 V

d) 24 V

e) 26 V

2. Find V2

a) 2V

b) 4V

c) 6 V

d) 24 V

e) 26 V

3. Find V3

a) 2V

b) 4V

c) 6 V

d) 24 V

e) 26 V

4. Find i1

a) 1 A

b) 2A

c) 3 A

d) 4 A

e) 5 A

5. Find i3

a) 1 A

b) 2A

c) 3 A

d) 4 A

e) 5 A

Answer 1

d) 24v explanation i_1 = 30/Req, R_eq = (3//6) + 8 = 3 times 6/3 + 6 + 8 = 2 + 8 implies i_1 = 30/10 = 3A = 2 + 8 implies R_eq = 10 ohm Now, v_1 = i_1 times 8 ohm v_1 = 3 times 8 = 24 v c) 6v explanation applying current division rule i_2 = i_1 times 6/3 + 6 implies i_2 = 3 times 6/9 = 2A Now, v_2 = i_2 times 3 ohm = 2 times 3 = 6v implies v_2 = 6v c) 6v explanation directly you can put as 6v since, the 6 ohm resistor is parallel with 3 ohm resisters in parallel circuit voltage resister same in series circuit current remains same \r\n i_3 = i_1 - i_2 = 3 - 2 = 1A then v_3 = i_3 times 6 ohm = 1 times 6 = 6v v_3 = 6v (or) current division i_3 = i_1 times 3/6 + 3 = 3 times 3/9 = 1A