Question

python please

11 def add_item(items, word): 14 15 16 F # check if the word is in the dictionary (keys of dictionary) if word in items: items [word] = items (word] + 1 # update the count else: # word is not in dictionary items[word] = 1 # add the word with count 1 return items [word] # return the current count of word after updation Create a function named build_dictionary that takes a list of words (as a parameter) and returns a dictionary that contains a count for each word from the list of words. The function build_dictionary will call add_item for every value in the list. After you are done, the following should work: sentence = "the quick brown fox jumped over the dog" words = sentence.split() d = build_dictionary(words) # should be True print(d["the" ] == 2) print(d["dog"] == sentence.count("dog")) If you need a refresher on split or count (see the lesson on strings) Hints: • Use membership notation to test if the key is in the dictionary (see previous lesson). • Do not use exception handling (next lesson) or any other viable methods we have not disussed yet (you can ONLY use what has been taught). • You can use the list of words in the variable named words) to test your function. • Do not use any global variables.

Answer 1

SOURCE CODE:

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**Please look at the Screenshot below and use this code to copy-paste.

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def add_item(items, word):
    # Check if the word is in the dictionary or not
    if word in items:
        items[word] += 1  # Update count
    else:  # Word not in the dictionary
        items[word] = 1  # add the word with count 1

    return items[word]  # Return the current count of word after updation


def build_dictionary(words):
    # Initialise an empty dictionary here
    items = {}
    # Use a for loop to traverse through each word in the words list
    for word in words:
        # Call the add_item method here
        add_item(items, word)

    # Return the items of dictionary
    return items


sentence = "the quick brown fox jumped over the dog"
words = sentence.split()
d=build_dictionary(words)

print(d["the"]==2)
print(d["dog"]==sentence.count("dog"))

=======================

SCREENSHOT:

$=========================================================== If\, there \,are \,any \,doubts,\, comment\, down \,here.\,\,\, \,We \,are\, right\, here\, to \,help\, you.\, \,\,\\{\color{Blue}Happy\,\, Learning..!!}\\\\ {\color{Red} PLEASE\,\,give \,\,an \,\,{\color{Blue} UPVOTE}\,\, I\,\,Have \,\,Put\,\,a \,\,lot\,\,of\,\,EFFORT\,\,in\,\,solving\,\,Your\,\,Problem.}\,\, \,It \,really\, Boosts \,us..!! \\ {\color{Red} PLEASE\,\,give \,\,an \,\,{\color{Blue} UPVOTE}\,\, I\,\,Have \,\,Put\,\,a \,\,lot\,\,of\,\,EFFORT\,\,in\,\,solving\,\,Your\,\,Problem.}\,\,, \,It \,really\, Boosts \,us..!! \\ ===========================================================$

Answer 2

def add_item(items, word):
    if word in items:
        items[word] = items[word] + 1
    else:
        items[word] = 1
    return items[word]


def build_dictionary(words):
    dict = {}

    # For every word 'w' in list word
    # Call function add_items
    for w in words:
        dict[w] = add_item(dict, w)

    # return dict
    return dict


if __name__ == '__main__':
    sentence = "the quick brown fox jumped over the dog"
    words = sentence.split()
    d = build_dictionary(words)

    print(d["the"] == 2)
    print(d["dog"] == sentence.count("dog"))

SCREENSHOT

CountWords.pyx def add item (items, word) 1 if word in items: 2 items [word] 1 items [word] = 4 else items [word] 1 = return items [word] 7 8 def build dictionary (words) dict 10 { } wwwwww 11 # For every word 'w' in list word 12 Call function add items 13 14 for w in words: dict [w add_item (dict, w) 15 16 return dict 17 18 return dict 19 20 if main_' 21 name 22 "the quick brown fox jumped over the dog" sentence = sentence.split() 23 words = build_dictionary (words) 24 d 25 print (d["the" 26 2) sentence.count ("dog")) print (d["dog"] 27 LC LC

OUTPUT

E\Practice\P True True Process finis