The vapor pressure of ethanol is 115 torr at 34.9 oC and ΔHvap of ethanol is 38.6 kJ/mol, use this information and the Clausius-Clapeyron equation (shown below) to calculate the temperature in oC at which the vapor pressure is 760 torr (remember to convert temperatures to K in the equation (K = oC + 273). R = 8.314 J/mol·K. ( Please show each step, step BY step) I am having difficult with finding T2
The vapor pressure of ethanol is 115 torr at 34.9 oC and ΔHvap of ethanol is...
The vapor pressure of ethanol is 115 torr at 34.9°C. If ΔHvap of ethanol is 38.6 kJ/mol, calculate the temperature (in °C) when the vapor pressure is 760 torr. When I plug everything in I get 1.888 = -4640 *(1/t2-3.247*10^-3) but my algebra is rusty and I don't get the same answer as the book. A detailed explanation would be greatly appreciated. Thanks! lnP2/P1= -Hvap/R*(1/t2-1/t)
The vapor pressure of ethanol is 1.00 x 102 mmHg at 34.90oC. What is its vapor pressure at 51.73 oC? (ΔHvap for ethanol is 39.3 Kj/mol.) Given the vapor pressure at one temperature, P1, we can calculate the vapor pressure at a second temperature, P2. In (P1/P2) = ΔHvap/R (1/T2 - 1/T1) Where, ΔHvap for ethanol must have the units of J/mol. R = 8.314 J/K.mol .. The temperatures must be in Kelvins. Solve for P2, What is the vapor...
Do sample problem 12.2. Use the Clausius-Clapeyron equation to
solve this problem.
At 34.1°C, the vapor pressure of water is 40.1 torr. What is the
vapor pressure (in torr) at 84.1°C? The ΔHvap of water
is 40.7 kJ/mol. Units need to match. R= 0.0821 l atm/mol K, R=
8.314 J/mol K.
(12.1) (一) - - 号
Use of Clausius-Clapeyron Equation 3- The vapor pressure of liquid ethanol at various temperatures is given below. Estimate the heat of vaporization of this compound at 170. oW. Pbuh (kPa) 0.6667 1.333 2.667 5.333 8.00 13.33 T (°C)12.0-2.3 8.0 19.0 26.0 34.9 Equations P (RT/V-b))-(a/(T V(V+b))) (0.42748 R2 Tc25 ) / Pc b (0.08664 R Te ) / Pe a
Use of Clausius-Clapeyron Equation 3- The vapor pressure of liquid ethanol at various temperatures is given below. Estimate the heat...
1. If the atmospheric pressure was 765 torr and the partial pressure of air was 745 torr, calculate the partial pressure of water vapor using Dalton's Law. Perial - P. + P2! 765 forr = 745 torr & P2 P = 20 tour -795 torre 2. Refer to the "y = mx + b" (linear) form of the Clausius-Clapeyron equation on the first page of this experiment. What part of the Clausius-Clapeyron equation is equal to the slope: slope =...
The vapor pressure of a substance is 760.0 torr at 115°C and 14.6 torr at 45°C. What is ΔHvap of the substance?
Calculate the vapor pressure of 3-pentanone (b.p. 102.0 °C) at the gas chromatography column temperature of 96.0"C using the form of the Clausius-Clapeyron equation shown below, P1 P. vap where R is the ideal gas constant, ???? is the enthalpy of vaporization, T1 and T2 are two different temperatures, and P1 and P2 are the vapor pressures at the respective temperatures. The enthalpy of vaporization can be estimated using Trouton's rule, ??'vap-(88 J mol-1 K-1), Tp. Number Torr Calculate the...
The vapor pressure if ethanol (C2H5OH) is 672 torr at 75°C. The vapor pressure of water is 289 torr at the same temperature. Calculate the mole fraction of ethonal and water in a solution that is 12% ethanol by volume. Can any one help me step-by-step with this?
Water has a vapor pressure of 23.8 mm Hg at 25°C and a heat of vaporization of 40.657 kJ/mol. Using the Clausius-Clapeyron equation given below, determine the vapor pressure of water at 96°C. ln P2 P1 = −ΔHvap R 1 T2 − 1 T1 _______________ mm Hg (pay attention to sig figs)
The vapor pressure of a liquid is the pressure exerted by its vapor when the liquid and vapor states are in equilibrium. The relationship between vapor pressure P and temperature T is expressed by the Clausius-Clapeyron equation. lnP2P1=ΔHvapR(1T1−1T2) where P1 and P2 are the vapor pressures at the absolute temperatures T1 and T2, respectively, ΔHvap is the heat of vaporization of the substance in joules per mole, and R is the ideal gas constant, which is equal to 8.3145 J/(mol⋅K)....