Homework Answers
Answer :- option E 25%(R) , 75%(S)
Solution :- Since we know that
R(-) and S(+) will cancel each other's rotation.
and also Mixture gives +ve rotation. So,(S)-(+)-2-butanol is in
excess.
lets assume x% of (S)-(+)-2-butanol and (100- x) %
(R)-(-)-2-butanol
then ;
+ 6.76 = (x/100)*(+13.52) + ((100 - x)/100)*(-13.52)
x= 75 = % of (S)-(+)-2-butanol
(100 - x) = 25 = % of (R)-(-)-2-butanol
So option E is correct
75 % S & 25% R
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