A survey asks a random sample of 1500 adults in Ohio if they support an increase in the state sales tax from 5% to 6%, with the additional revenue going to education. Let p denote the proportion in the sample who say they support the increase. Suppose that 55% of all adults in Ohio support the increase. The st deviation of the sampling distribution is _______
7)
Solution
Given that,
p = 55% = 0.55
1 - p = 1 - 0.55 = 0.45
n = 1500
The standard deviation of the sampling distribution is ,

=
p
( 1 - p ) / n

=
(0.55 * 0.45) / 1500 =
0.000165

= 0.0128
The standard deviation of the sampling distribution is 0.0128 .
A survey asks a random sample of 1500 adults in Ohio if they support an increase
A survey asks a random sample of 1500 adults in Ohio if they support an increase in the state sales tax from 5% to 6%, with the additional revenue going to education. Let P denote the proportion in the sample who say they support the increase. Suppose that 54% of all adults in Ohio support the increase. The standard deviation of the sampling distribution is...? Round your answer to four decimal places.
A survey asks a random sample of 1500 adults in Ohio if they support an increase in the state sales tax from 5% to 6%, with the additional revenue going to education. Let ^ p denote the proportion in the sample who say they support the increase. Suppose that 36% of all adults in Ohio support the increase. The standard deviation of the sampling distribution is . Round your answer to four decimal places.
Question 2 A survey asks a random sample of 1500 adults in Virginia if they support an increase in the sales tax from 5% to 6%, with the additional revenue going to education. Let p denote the proportion in the sample who say they support the increase. Suppose that 40% of all adults in Virginia support the increase. A.) Find the probability that p takes a value between 0.37 and 0.43. (5 points) B.) what's the probability that a majority...
1. Suppose that a survey asks a random sample of 1500 adults in Ohio if they support an increase in the state sales tax. Suppose that 40% of all adults in Ohio support the increase. We independently select 7 adults at random and record their status in supporting the increase. What is the probability that exactly 4 people support the increase in tax? Group of answer choices 0.2419 0.5162 0.1935 0.4838 2. A sample of 24 observations is taken from...
Question1 Not complete Points out of 1.00 A Simple Random Sample of fish is taken from a population that has a mean length of 80 cm and a standard deviation of 20 cm. How large of a sample is needed so that the sampling distribution of the sample proportion has a standard deviation of 1 cm? Flag question Select one: a. 400 b. 20 d. 80 Check Question 2 Not complete Points out of 1.00 The World Health Organization estimates...
Question 3 Not complete Points out of 1.00 As part of a promotion for a new type of cracker, free samples are offered to shoppers in a local supermarket. The probability that a shopper will buy a packet of crackers after tasting the free sample is 0.200. Different shoppers can be regarded as independent trials. Let p be the proportion of the next n shoppers that buy a packet of the crackers after tasting a free sample. How large should...
A random sample of 100 registered voters in Columbia SC was selected for a phone survey. The key question was "Do You Approve or Disapprove of Governor McMaster’s Job Performance?" Assume the population proportion that approve of the Governor’s performance is known to be 55%. (a) (5 points) Describe the shape of the sampling distribution. How do you know it is this shape? Find the mean and standard deviation for the distribution of the sample proportion pˆ of voters who...
In a random sample of 64 audited estate tax returns, it was determined that the mean amount of additional tax owed was $3435 with standard deviation of $2559. Construct and interpret a 90% confidence interval for the mean additional amount of tax owed for estate tax returns. Click the icon to view the t-distribution table. The lower bound is $. (Round to the nearest dollar as needed.) The upper bound is $(Round to the nearest dollar as needed.) Interpret a...
A recent survey of 1500 residents in a city indicated that around 40% of the residents owned a home. Suppose that it is indeed true that 40% of the residents own a home. The sampling distribution for the proportion of home ownership is approximately normal with mean 0.40 and standard deviation 0.025. What is the probability the sample proportion of people who own a home will be less than 0.37?
According to a survey in a country, 25% of adults do not have any credit cards. Suppose a simple random sample of 600 adults is obtained. (a) Describe the sampling distribution of p, the sample proportion of adults who do not have a credit card. Choose the phrase that best describes the shape of the sampling distribution of p below. O A. Not normal because ns0.05N and np(1 - p) < 10. B. Approximately normal because ns0.05N and np(1 –...