Question

Question 2 How much concrete (CY) is required for an 7 inch thick slab for a building with an 54 foot by 123 foot footprint? Question 3 If 14.25 ft of cement are used in making a batch of concrete and using the 1:2:3 ratio of cement to sand to aggregate, how many cubic yards of concrete can be made? Question 4 How much concrete (CY) is required for a foundation wall with the following dimensions: - Thickness = 8 inches - Height = 5 feet Building Footprint = 59 feet by 86 feet

Answer 1

2) Thickness = Tin = 7/12 Ft : Area = $548123 Fť? Volume = Thickness & Area = I x 54X123 = 3874.5 Ft 1 cubic Feet = 0.03703 TOST cubic yards (C4) .: Concrete volume required = 3874.5*0.037037037 = 143.5 ch 3) JO U Cement: Sand: Aggregate = 1:2:3 Volume of concrete = volume of (Cement & Sand & Aggregate) Volume of cement = 14.25 ft 3 het cement volume be a then sand volume = 2n , Aggregate volume = 3x. : Total concrete volume = x + 2x+8 x = Gr. x is givers by 14.25 ft 3 .: Total concrete volume = 6 x 14.25 = 85.5 ft 3

| 1 ft 3 = 0,0370 37631 c Vokeme of concrete = 85.5X0.037037037 = 3.167 CM 4 Thickness = 8 in Height =5ft, Footprint = 59x86 Ft 2, 1591 gy - . - 86-8/1272 8"! 59-2X8/12 Exterior area = 59886 , Interior area = (50 - 5074 ft? - 4882,44 Ft 2 .: Area of wall foundation =5074-4882.44 = 192.56 ft² wall foundation = 5ft Volume of wall foundation = 191.56x 5 = 957.8 ft 3 - 95 1.8 X 0.037037037 = 35.474 Cubic Cards (64)