Question

Find the currents i1, i2 and i3 in the circuit shown. 4S2 8Ω +30V i 12 22 ) 12Ω

Answer 1

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Apply looping in the circuits by inspection method in loop 1 I_1 = 4.5 A 1 In loop 2 21I_2 - 1 I_1 - 12I_3 = 0 implies 21I_2 - 4.5 - 12I_3 = 0 using 1 implies 21I_2 - 12I_3 = 4.5 2 In loop 3 16I_3 - 12I_2 = 30 3 using 2 & 3 I_2 = 2.25 Amp I-3 = 3.56 Amp 21I_2 = 4.5 + 2 I_3 implies I_2 = 4.5 + 12 I_3/21 implies I_2 value in equation 3 16 I_3 - 12(4.5 + 12I_3/21) = 30 implies I_3 = 3.56, I_2 = 2.25